Unit 1: Limit, Continuity, and Differentiation

Table of Contents

Limit (ε-δ definition)

The concept of a limit is the foundation of calculus. It describes the value that a function f(x) "approaches" as the input x "approaches" some value a.

Formal (Epsilon-Delta) Definition

We say that the limit of f(x) as x approaches 'a' is L, written as: lim (x → a) f(x) = L if for every number ε > 0 (epsilon), there exists a corresponding number δ > 0 (delta) such that if 0 < |x - a| < δ, then |f(x) - L| < ε.

Understanding the Definition

In simple terms: You can make f(x) as close as you want (within ε) to L, just by making x close enough (within δ) to 'a'.

Exam Tip: A common exam question is to use the ε-δ definition to prove a simple limit.
Example: Prove lim (x → 2) (3x + 1) = 7.
  1. Setup: We need to show that for any ε > 0, we can find a δ > 0 such that if 0 < |x - 2| < δ, then |(3x + 1) - 7| < ε.
  2. Work backwards (Scratch work): Start with the "then" part: |(3x + 1) - 7| < ε
    |3x - 6| < ε
    |3(x - 2)| < ε
    3 * |x - 2| < ε
    |x - 2| < ε / 3
  3. Choose δ: This scratch work tells us what to choose for δ. We can choose δ = ε / 3.
  4. Formal Proof: Given ε > 0, choose δ = ε / 3.
    If 0 < |x - 2| < δ, then:
    |x - 2| < ε / 3
    3 * |x - 2| < ε
    |3x - 6| < ε
    |(3x + 1) - 7| < ε
    Thus, by definition, lim (x → 2) (3x + 1) = 7.

Cauchy's Criterion for Existence of Limit

This is a theoretical test for the existence of a limit that does not require knowing the value (L) of the limit beforehand.

Statement (without proof)

The limit lim (x → a) f(x) exists if and only if for every ε > 0, there exists a δ > 0 such that for any two points x₁ and x₂ in the deleted neighborhood of 'a' (i.e., 0 < |x₁ - a| < δ and 0 < |x₂ - a| < δ), we have: |f(x₁) - f(x₂)| < ε

In simple terms: A limit exists if, as x gets closer and closer to 'a', the corresponding values of f(x) get closer and closer to each other.

Problems Related to Existence of Limit

The most common problems involve checking if the Left-Hand Limit (LHL) and Right-Hand Limit (RHL) are equal.

Existence of a Limit: lim (x → a) f(x) exists if and only if LHL = RHL (and both are finite).

Example: Does the limit of f(x) = |x| / x exist at x = 0?

  1. Find LHL: lim (x → 0⁻) f(x)
    When x < 0, |x| = -x.
    So, f(x) = (-x) / x = -1.
    LHL = lim (x → 0⁻) (-1) = -1.
  2. Find RHL: lim (x → 0⁺) f(x)
    When x > 0, |x| = x.
    So, f(x) = x / x = 1.
    RHL = lim (x → 0⁺) (1) = 1.
  3. Conclusion: Since LHL (-1) ≠ RHL (1), the limit does not exist at x = 0.

Continuity and Related Theorems

Definition of Continuity

A function f(x) is said to be continuous at a point x = a if it satisfies all three of the following conditions:

  1. f(a) is defined (the point exists on the graph).
  2. lim (x → a) f(x) exists (the LHL equals the RHL).
  3. lim (x → a) f(x) = f(a) (the limit value is the same as the function's value).

If any of these conditions fail, the function is discontinuous at x = a.

Related Theorems (without proof)

These theorems (stated without proof as per the syllabus) describe how continuity behaves with arithmetic operations.

If f(x) and g(x) are both continuous at x = a, then:

Exam Tip: Problems on continuity often involve piecewise functions. You'll be asked to find a value of a constant (e.g., 'k') that makes the function continuous.
Strategy:
  1. Find the LHL at the point where the function's definition changes.
  2. Find the RHL at that same point.
  3. Find the value of the function at that point, f(a).
  4. Set LHL = RHL = f(a) and solve for the constant 'k'.

Types of Discontinuities

Type of Discontinuity Condition Example
Removable Discontinuity lim (x → a) f(x) exists, but is not equal to f(a) (or f(a) is undefined). This is a "hole" in the graph. f(x) = (x² - 4) / (x - 2) at x = 2. (The limit is 4, but f(2) is undefined).
Jump Discontinuity (First Kind) LHL and RHL both exist (are finite), but are not equal. f(x) = |x| / x at x = 0. (LHL = -1, RHL = 1).
Infinite Discontinuity (Second Kind) At least one of the LHL or RHL is infinite (or does not exist). This is a vertical asymptote. f(x) = 1 / x at x = 0. (LHL = -∞, RHL = +∞).
Oscillating Discontinuity (Second Kind) The function oscillates infinitely as x approaches 'a', so the limit does not exist. f(x) = sin(1/x) at x = 0.

Differentiability

Definition of Differentiability

A function f(x) is differentiable at a point x = a if the following limit exists:

f'(a) = lim (h → 0) [f(a + h) - f(a)] / h

This limit, f'(a), is called the derivative of f(x) at x = a. It represents the instantaneous rate of change, or the slope of the tangent line to the curve y = f(x) at x = a.

Left-Hand and Right-Hand Derivatives

A function is differentiable at 'a' if and only if LHD = RHD (and both are finite).

Application of Differentiability

Theorem: Differentiability implies Continuity. If a function f(x) is differentiable at x = a, then it must be continuous at x = a.
Converse is NOT true: Continuity does NOT imply Differentiability. A function can be continuous at a point but not differentiable there.
Classic Example: The function f(x) = |x| at x = 0.

Geometrical Reason: The graph of y = |x| has a sharp corner at x = 0, so there is no unique tangent line.

Successive Differentiation

Successive differentiation means differentiating a function repeatedly.

Finding a general formula for the n-th derivative is a key skill. This is usually done by calculating the first few derivatives (f', f'', f''') and looking for a pattern.

Function, y = f(x) n-th Derivative, yⁿ
eᵃˣ aⁿ * eᵃˣ
(ax + b)ᵐ aⁿ * [m! / (m-n)!] * (ax + b)ᵐ⁻ⁿ
1 / (ax + b) (-1)ⁿ * n! * aⁿ * (ax + b)⁻(ⁿ⁺¹)
ln(ax + b) (-1)ⁿ⁻¹ * (n-1)! * aⁿ * (ax + b)⁻ⁿ
sin(ax + b) aⁿ * sin(ax + b + nπ/2)
cos(ax + b) aⁿ * cos(ax + b + nπ/2)

Leibnitz's Theorem

This theorem provides a formula for the n-th derivative of a product of two functions.

If y = u * v, where u and v are functions of x, then the n-th derivative of y is: (uv)ⁿ = ⁿC₀ uⁿv + ⁿC₁ uⁿ⁻¹v¹ + ⁿC₂ uⁿ⁻²v² + ... + ⁿCᵣ uⁿ⁻ʳvʳ + ... + ⁿCₙ uvⁿ Where:

Application of Leibnitz's Theorem

This theorem is most useful when one of the functions (say, v) is a polynomial (like x², x³). After a few derivatives, the derivatives of v will become zero, making the series finite and easy to calculate.

Example: Find the n-th derivative of y = x² * eᵃˣ.

  1. Let u = eᵃˣ (because its n-th derivative is easy to find) and v = x² (because its derivatives become zero).
  2. Find the derivatives of u and v:
    • v = x²
    • v¹ = 2x
    • v² = 2
    • v³ = 0 (and all higher derivatives are 0)
    • uⁿ = aⁿeᵃˣ
    • uⁿ⁻¹ = aⁿ⁻¹eᵃˣ
    • uⁿ⁻² = aⁿ⁻²eᵃˣ
  3. Apply the formula (it will stop after the v² term): yⁿ = (ⁿC₀ uⁿv) + (ⁿC₁ uⁿ⁻¹v¹) + (ⁿC₂ uⁿ⁻²v²)
  4. Substitute the parts (remember ⁿC₀ = 1, ⁿC₁ = n, ⁿC₂ = n(n-1)/2): yⁿ = (1 * aⁿeᵃˣ * x²) + (n * aⁿ⁻¹eᵃˣ * 2x) + ([n(n-1)/2] * aⁿ⁻²eᵃˣ * 2)
  5. Simplify the expression: yⁿ = aⁿeᵃˣx² + 2naⁿ⁻¹eᵃˣx + n(n-1)aⁿ⁻²eᵃˣ yⁿ = aⁿ⁻²eᵃˣ * [a²x² + 2nax + n(n-1)]