Simple Harmonic Motion (SHM) is a special type of periodic motion where the restoring force (F) is directly proportional to the displacement (x) from the equilibrium position and acts in the opposite direction.
This is Hooke's Law: F = -kx
            
Where `k` is the force constant (or spring constant).
        
Using Newton's Second Law, F = ma:
ma = -kx
m(d²x/dt²) = -kx
m(d²x/dt²) + kx = 0
Dividing by `m`, we get the standard form:
d²x/dt² + (k/m)x = 0
We define the natural angular frequency (ω₀) as:
ω₀² = k/m (or ω₀ = √(k/m))
So the differential equation becomes:
d²x/dt² + ω₀²x = 0
This is a second-order homogeneous differential equation. The general solution can be written in several equivalent forms:
x(t) = A cos(ω₀t + φ)
Velocity and Acceleration in SHM:
K = (1/2)mv² = (1/2)m [-Aω₀ sin(ω₀t + φ)]²
K(t) = (1/2)mω₀²A² sin²(ω₀t + φ)
Since ω₀² = k/m, this is also K(t) = (1/2)kA² sin²(ω₀t + φ).
For a spring system, U = (1/2)kx² = (1/2)k [A cos(ω₀t + φ)]²
U(t) = (1/2)kA² cos²(ω₀t + φ)
E = K(t) + U(t) = (1/2)kA² sin²(ω₀t + φ) + (1/2)kA² cos²(ω₀t + φ)
Using the identity sin²θ + cos²θ = 1:
E = (1/2)kA² = constant
The total mechanical energy in an *undamped* simple harmonic oscillator is constant and is proportional to the square of the amplitude.
The average value of a function `f(t)` over one period `T` is `(1/T) ∫[0, T] f(t) dt`.
The key trigonometric identity is that the average value of sin²(θ) or cos²(θ) over one full period is 1/2.
= (1/4)kA² = (1/2) E 
= <(1/2)kA² cos²(ω₀t + φ)>
 = (1/2)kA² * 
= (1/4)kA² = (1/2) E
Conclusion: For SHM, the average kinetic energy is equal to the average potential energy, and each is equal to half the total energy.
This is a more realistic model of an oscillator, which includes a damping force (like friction or air resistance) that opposes the motion. This force is typically modeled as being proportional to the velocity:
Fdamping = -bv (where `b` is the damping coefficient)
The total force is now Fnet = Frestoring + Fdamping = -kx - bv
The differential equation becomes:
m(d²x/dt²) = -kx - b(dx/dt)
m(d²x/dt²) + b(dx/dt) + kx = 0
We define the damping constant γ = b/m (some books use 2γ = b/m, be careful). Let's use 2β = b/m for simplicity in the solution (where β is the decay constant).
d²x/dt² + (b/m)(dx/dt) + (k/m)x = 0
d²x/dt² + 2β(dx/dt) + ω₀²x = 0 (where β = b/2m and ω₀² = k/m)
The solution to this equation is:
x(t) = A0 e-βt cos(ω't + φ)
This is an oscillation `cos(ω't + φ)` with an exponentially decaying amplitude `A(t) = A₀e⁻ᵇᵗ`.
The new angular frequency `ω'` is slower than the natural frequency `ω₀`:
ω' = √(ω₀² - β²) = √( (k/m) - (b/2m)² )
Three Cases of Damping:
This is a damped oscillator that is also pushed by an external, periodic driving force. Let the driving force be `F_drive = F₀ cos(ωt)` (where `ω` is the driving frequency, which is *not* the same as `ω₀` or `ω'`).
The full differential equation is:
m(d²x/dt²) + b(dx/dt) + kx = F₀ cos(ωt)
The general solution is `x(t) = x_c(t) + x_p(t)`.
The steady-state solution `x_p(t)` is an oscillation at the *driving frequency* `ω`, but with a phase shift `φ` relative to the driver:
x(t) = A(ω) cos(ωt - φ)
The Amplitude A(ω) of this steady-state motion depends on the driving frequency `ω`:
A(ω) = (F₀/m) / √[ (ω₀² - ω²)² + (bω/m)² ]
This amplitude `A(ω)` is small when `ω` is very low or very high. It becomes maximum when the driving frequency `ω` is *close* to the natural frequency `ω₀`.
Resonance is the phenomenon where the amplitude of a forced oscillator becomes very large when the driving frequency (ω) is tuned to a specific value, called the resonance frequency (ωR).
The resonance frequency is:
ωR = √(ω₀² - 2β²) = √( (k/m) - b²/2m² )
The "sharpness" describes how narrow the resonance peak is.
In a damped (or forced) oscillator, energy is continuously lost (dissipated) by the damping force `F_damping = -bv`.
        
The instantaneous power dissipated is P(t) = F_damping * v = (-bv) * v = -bv².
The average power dissipated `
` in the steady-state of a forced oscillator is:
= (1/2) b ω² A(ω)²
This power is supplied by the driving force. At resonance, the amplitude `A` is max, so the power transfer from the driver to the oscillator is also maximum.
The Q Factor is a dimensionless parameter that describes how "good" an oscillator is (how low its damping is). A high Q-factor means low damping.
It can be defined in several equivalent ways:
Q = 2π * (Energy Stored in Oscillator / Energy Lost per Cycle)
Q = ω₀ / (b/m) = ω₀ / (2β)
Q ≈ ω₀ / ΔωA high Q-factor means a small Δω, which is a very sharp resonance.
(This topic was introduced in Unit 1 and is expanded here.)
Recall: A non-inertial frame is an accelerating frame of reference. In such a frame, Newton's 1st Law (inertia) fails. Objects appear to accelerate without a real force.
To "fix" Newton's 2nd Law (F=ma) so we can still use it in a non-inertial frame, we must invent fictitious forces (or pseudo-forces). These are not real forces (not part of a 3rd Law pair) but are mathematical corrections due to the frame's acceleration.
Let `a_inertial` be the true acceleration of an object in an inertial frame, and `a_non_inertial` be its acceleration *as measured by an observer* in the non-inertial frame.
        
Let `A` be the acceleration of the non-inertial frame itself (relative to the inertial frame).
The relationship is: ainertial = anon_inertial + A
Now, Newton's 2nd Law (which is only valid in the inertial frame) is:
Freal = m ainertial = m(anon_inertial + A)
Freal = m anon_inertial + mA
Rearranging this to look like F=ma *in the non-inertial frame*:
m anon_inertial = Freal - mA
We define the fictitious force (Ffict) as:
Ffict = -m A
So, the "law" in the non-inertial frame becomes:
m anon_inertial = Freal + Ffict
Example: A person of mass `m` in an elevator accelerating upwards with `A = +aĵ`.
A uniformly rotating frame (like the Earth) is a non-inertial frame. The full fictitious force equation for a rotating frame is more complex. It has two parts:
Ffict = Fcentrifugal + FCoriolis
This is the familiar "force" that seems to "fling" objects outward from the center of rotation.
Fcentrifugal = -m (ω × (ω × r))
Magnitude: For circular motion, this simplifies to Fcentrifugal = +mω²r, directed radially outward.
This is the force you "feel" on a merry-go-round. It's just your body's inertia (its desire to go in a straight line) being interpreted as an outward force in the rotating frame.
This is a more subtle fictitious force that acts only on objects that are moving relative to the rotating frame.
FCoriolis = -2m (ω × vnon_inertial)
Where `ω` is the angular velocity vector of the frame and `v_non_inertial` is the object's velocity *as measured in the rotating frame*.
Characteristics: