Unit 1: Vectors and Differential Equations

Table of Contents

Vector Algebra

Dot and Cross product and their properties

Scalar (Dot) Product: A product of two vectors that results in a scalar.

A · B = |A| |B| cos(θ)

Vector (Cross) Product: A product of two vectors that results in a new vector.

A × B = |A| |B| sin(θ) n̂

Where n̂ is a unit vector perpendicular to the plane of A and B, given by the Right-Hand Rule.

Scalar and Vector triple products

Scalar Triple Product (Box Product):

A · (B × C)

Vector Triple Product:

A × (B × C)
Common Mistake: Confusing the two triple products. Remember `A · (B × C)` gives a scalar (volume) and can be calculated with a 3x3 determinant. `A × (B × C)` gives a vector and is solved with the BAC-CAB rule.

Vector Calculus: Grad, Div, Curl

This section introduces the vector differential operator del ().

In Cartesian coordinates: = î (∂/∂x) + ĵ (∂/∂y) + k̂ (∂/∂z)

Gradient (grad) and its significance

The gradient acts on a scalar field (f) and produces a vector field.

grad(f) = ∇f = (∂f/∂x)î + (∂f/∂y)ĵ + (∂f/∂z)k̂

Physical Significance:

Divergence (div) and its significance

The divergence acts on a vector field (V) and produces a scalar field.

div(V) = ∇ · V = (∂Vx/∂x) + (∂Vy/∂y) + (∂Vz/∂z)

Physical Significance:

Curl and its significance

The curl acts on a vector field (V) and produces another vector field.

        |  î     ĵ     k̂   |
curl(V) = ∇ × V = | ∂/∂x  ∂/∂y  ∂/∂z |
        |  Vx    Vy    Vz  |
            

Physical Significance:


Vector Integration

The syllabus specifies "statement only," so we will define the integrals and their primary meaning.

Line Integral

I = ∫C V · dr

This represents the integral of the component of a vector field V that is tangent to a path C.
Application: Calculating the Work done by a force field F along a path: W = ∫ F · dr.

Surface Integral

Φ = ∫∫S V · dS

This represents the integral of the component of a vector field V that is normal to a surface S.
Application: Calculating the Flux of a field (e.g., electric flux, magnetic flux) through a surface.

Volume Integral

Q = ∫∫∫V f dV

This represents the integral of a scalar field f (like density) over a 3D volume V.
Application: Calculating the total quantity (e.g., total mass, total charge) inside a volume.


1st Order Homogeneous Differential Equations

This refers to linear homogeneous equations of the form:

dy/dx + P(x)y = 0

This type of equation is fundamental in physics, describing processes like radioactive decay or the discharge of a capacitor.

Solution Method (Separation of Variables)

  1. Rearrange the equation:
    dy/dx = -P(x)y
  2. Separate the variables (bring all 'y' terms to one side, 'x' terms to the other):
    dy / y = -P(x) dx
  3. Integrate both sides:
    ∫ (1/y) dy = -∫ P(x) dx + C'
    ln(y) = -∫ P(x) dx + C'
  4. Solve for y by taking the exponential of both sides:
    y = e(-∫P(x)dx + C') = e-∫P(x)dx * eC'
  5. Let the constant `e^C'` be `C`. The general solution is:
    y(x) = C e-∫P(x)dx
Example (Radioactive Decay):
The rate of decay (dN/dt) is proportional to the number of atoms (N).
dN/dt = -λN (where λ is the decay constant)
This is a 1st order homogeneous ODE.
dN/N = -λ dt
∫ dN/N = ∫ -λ dt
ln(N) = -λt + C'
N(t) = e-λt + C' = (eC') e-λt
Let N₀ be the number at t=0. N₀ = (eC')e⁰ → eC' = N₀.
Solution: N(t) = N₀ e-λt

2nd Order Homogeneous Differential Equations with Constant Coefficients

This is one of the most important equations in physics, as it describes all types of oscillations (Simple Harmonic Motion, Damped Oscillations).

The general form is:

a (d²y/dx²) + b (dy/dx) + c y = 0

where `a`, `b`, and `c` are constants.

Solution Method (Auxiliary Equation)

  1. Assume a trial solution of the form y = emx.
  2. Substitute this into the ODE:
    y' = memx
    y'' = m²emx
    a(m²emx) + b(memx) + c(emx) = 0
  3. Factor out emx (which is never zero):
    emx (am² + bm + c) = 0
  4. This leaves the Auxiliary (or Characteristic) Equation:
    am² + bm + c = 0
  5. Solve this quadratic equation for its roots, m₁ and m₂. The form of the general solution `y(x)` depends on the nature of these roots.

Three Cases for the Solution

Case (based on discriminant b²-4ac) Roots (m₁, m₂) General Solution y(x) Physical Example (in time)
Case 1: Real and Distinct
(b²-4ac > 0)
m₁ and m₂ are real, m₁ ≠ m₂ y = C₁em₁x + C₂em₂x Overdamped motion
Case 2: Real and Equal
(b²-4ac = 0)
m₁ = m₂ = m (real) y = (C₁ + C₂x)emx Critically Damped motion
Case 3: Complex Conjugate
(b²-4ac < 0)
m = α ± iβ y = eαx (C₁cos(βx) + C₂sin(βx)) Underdamped (Oscillatory) motion
Example (Simple Harmonic Motion):
d²x/dt² + (k/m)x = 0 or x'' + ω₀²x = 0
Here, `a=1`, `b=0`, `c=ω₀²`.
Auxiliary Equation: m² + ω₀² = 0
Roots: m² = -ω₀² → m = ±√(-ω₀²) = ± iω₀.
This is Case 3, with α = 0 and β = ω₀.
Solution: x(t) = e0t (C₁cos(ω₀t) + C₂sin(ω₀t))
x(t) = C₁cos(ω₀t) + C₂sin(ω₀t), which is the standard SHM solution.